Natalie and Elyse have some stickers. If Natalie gives 15 stickers to Elyse, Elyse will have 4 times the number of stickers as Natalie. If Elyse gives 33 stickers to Natalie, Natalie will have
25 as many stickers as Elyse. How many stickers does Natalie have at first?
|
Case 1 |
Case 2 |
|
Natalie |
Elyse |
Natalie |
Elyse |
Before |
7 u + 15 |
28 u - 15 |
10 u - 33 |
25 u + 33 |
Change |
- 15 |
+ 15 |
+ 33 |
- 33 |
After |
1x7 = 7 u |
4x7 = 28 u |
2x5 = 10 u |
5x5 = 25 u |
The total number of stickers in both cases remains unchanged. Make the total number of stickers in both cases the same. LCM of 5 and 7 is 35.
Number of stickers that Natalie had at first is the same in both cases.
10 u - 33 = 7 u + 15
10 u - 7 u = 15 + 33
3 u = 48
1 u = 16
Number of stickers that Natalie had at first
= 7 u + 15
= 7 x 16 + 15
= 112 + 15
= 127
Answer(s): 127