Wendy and Fanny have some coins. If Wendy gives 29 coins to Fanny, Fanny will have 5 times the number of coins as Wendy. If Fanny gives 41 coins to Wendy, Wendy will have
25 as many coins as Fanny. How many coins does Wendy have at first?
|
Case 1 |
Case 2 |
|
Wendy |
Fanny |
Wendy |
Fanny |
Before |
7 u + 29 |
35 u - 29 |
12 u - 41 |
30 u + 41 |
Change |
- 29 |
+ 29 |
+ 41 |
- 41 |
After |
1x7 = 7 u |
5x7 = 35 u |
2x6 = 12 u |
5x6 = 30 u |
The total number of coins in both cases remains unchanged. Make the total number of coins in both cases the same. LCM of 6 and 7 is 42.
Number of coins that Wendy had at first is the same in both cases.
12 u - 41 = 7 u + 29
12 u - 7 u = 29 + 41
5 u = 70
1 u = 14
Number of coins that Wendy had at first
= 7 u + 29
= 7 x 14 + 29
= 98 + 29
= 127
Answer(s): 127