Marion and Tina have some beads. If Marion gives 10 beads to Tina, Tina will have 5 times the number of beads as Marion. If Tina gives 25 beads to Marion, Marion will have
23 as many beads as Tina. How many beads does Marion have at first?
|
Case 1 |
Case 2 |
|
Marion |
Tina |
Marion |
Tina |
Before |
5 u + 10 |
25 u - 10 |
12 u - 25 |
18 u + 25 |
Change |
- 10 |
+ 10 |
+ 25 |
- 25 |
After |
1x5 = 5 u |
5x5 = 25 u |
2x6 = 12 u |
3x6 = 18 u |
The total number of beads in both cases remains unchanged. Make the total number of beads in both cases the same. LCM of 6 and 5 is 30.
Number of beads that Marion had at first is the same in both cases.
12 u - 25 = 5 u + 10
12 u - 5 u = 10 + 25
7 u = 35
1 u = 5
Number of beads that Marion had at first
= 5 u + 10
= 5 x 5 + 10
= 25 + 10
= 35
Answer(s): 35