Min and Winnie have some erasers. If Min gives 32 erasers to Winnie, Winnie will have 4 times the number of erasers as Min. If Winnie gives 16 erasers to Min, Min will have
25 as many erasers as Winnie. How many erasers does Min have at first?
|
Case 1 |
Case 2 |
|
Min |
Winnie |
Min |
Winnie |
Before |
7 u + 32 |
28 u - 32 |
10 u - 16 |
25 u + 16 |
Change |
- 32 |
+ 32 |
+ 16 |
- 16 |
After |
1x7 = 7 u |
4x7 = 28 u |
2x5 = 10 u |
5x5 = 25 u |
The total number of erasers in both cases remains unchanged. Make the total number of erasers in both cases the same. LCM of 5 and 7 is 35.
Number of erasers that Min had at first is the same in both cases.
10 u - 16 = 7 u + 32
10 u - 7 u = 32 + 16
3 u = 48
1 u = 16
Number of erasers that Min had at first
= 7 u + 32
= 7 x 16 + 32
= 112 + 32
= 144
Answer(s): 144