Two hours ago, a stallholder started his day with some kiwis and chikoos in the ratio of 5 : 4. There were 220 chikoos. Some of the kiwis were bought by Irene. As a result, the number of kiwis became
45 of the chikoos.
- How many kiwis did the stallholder have at first?
- How many chikoos did the stallholder have to sell in order to have an equal number of kiwis and chikoos?
|
Kiwis |
Chikoos |
Before |
5x5 = 25 u |
4x5 = 20 u |
Change |
- ? |
|
After |
4x4 = 16 u |
5x4 = 20 u |
(a)
The number of chikoos remains unchanged. Make the number of chikoos the same. LCM of 4 and 5 is 20.
20 u = 220
1 u = 220 ÷ 20 = 11
Number of kiwis that the stallholder had at first
= 25 u
= 25 x 11
= 275
(b)
Number of chikoos that the stallholder had to sell to have an equal number of kiwis and chikoos
= 20 u - 16 u
= 4 u
= 4 x 11
= 44
Answer(s): (a) 275; (b) 44