Five hours ago, a store owner started his day with some kiwis and oranges in the ratio of 5 : 2. There were 90 oranges. Some of the kiwis were bought by Shiyun. As a result, the number of kiwis became
45 of the oranges.
- How many kiwis did the store owner have at first?
- How many oranges did the store owner have to sell in order to have an equal number of kiwis and oranges?
|
Kiwis |
Oranges |
Before |
5x5 = 25 u |
2x5 = 10 u |
Change |
- ? |
|
After |
4x2 = 8 u |
5x2 = 10 u |
(a)
The number of oranges remains unchanged. Make the number of oranges the same. LCM of 2 and 5 is 10.
10 u = 90
1 u = 90 ÷ 10 = 9
Number of kiwis that the store owner had at first
= 25 u
= 25 x 9
= 225
(b)
Number of oranges that the store owner had to sell to have an equal number of kiwis and oranges
= 10 u - 8 u
= 2 u
= 2 x 9
= 18
Answer(s): (a) 225; (b) 18