Four hours ago, a grocer started his day with some chikoos and oranges in the ratio of 7 : 3. There were 60 oranges. Some of the chikoos were bought by Abi. As a result, the number of chikoos became
25 of the oranges.
- How many chikoos did the grocer have at first?
- How many oranges did the grocer have to sell in order to have an equal number of chikoos and oranges?
|
Chikoos |
Oranges |
Before |
7x5 = 35 u |
3x5 = 15 u |
Change |
- ? |
|
After |
2x3 = 6 u |
5x3 = 15 u |
(a)
The number of oranges remains unchanged. Make the number of oranges the same. LCM of 3 and 5 is 15.
15 u = 60
1 u = 60 ÷ 15 = 4
Number of chikoos that the grocer had at first
= 35 u
= 35 x 4
= 140
(b)
Number of oranges that the grocer had to sell to have an equal number of chikoos and oranges
= 15 u - 6 u
= 9 u
= 9 x 4
= 36
Answer(s): (a) 140; (b) 36