Four hours ago, a stallholder started his day with some chikoos and pears in the ratio of 7 : 3. There were 96 pears. Some of the chikoos were bought by Roshel. As a result, the number of chikoos became
34 of the pears.
- How many chikoos did the stallholder have left?
- How many chikoos did the stallholder have to buy in order to have an equal number of chikoos and pears?
|
Chikoos |
Pears |
Before |
7x4 = 28 u |
3x4 = 12 u |
Change |
- ? |
|
After |
3x3 = 9 u |
4x3 = 12 u |
(a)
The number of pears remains unchanged. Make the number of pears the same. LCM of 3 and 4 is 12.
12 u = 96
1 u = 96 ÷ 12 = 8
Number of chikoos that the stallholder had left
= 9 u
= 9 x 8
= 72
(b)
Number of chikoos that the stallholder had to buy to have an equal number of chikoos and pears
= 12 u - 9 u
= 3 u
= 3 x 8
= 24
Answer(s): (a) 72; (b) 24