Two hours ago, a store owner started his day with some chikoos and oranges in the ratio of 7 : 2. There were 90 oranges. Some of the chikoos were bought by Fanny. As a result, the number of chikoos became
25 of the oranges.
- How many chikoos did the store owner have left?
- How many chikoos did the store owner have to buy in order to have an equal number of chikoos and oranges?
|
Chikoos |
Oranges |
Before |
7x5 = 35 u |
2x5 = 10 u |
Change |
- ? |
|
After |
2x2 = 4 u |
5x2 = 10 u |
(a)
The number of oranges remains unchanged. Make the number of oranges the same. LCM of 2 and 5 is 10.
10 u = 90
1 u = 90 ÷ 10 = 9
Number of chikoos that the store owner had left
= 4 u
= 4 x 9
= 36
(b)
Number of chikoos that the store owner had to buy to have an equal number of chikoos and oranges
= 10 u - 4 u
= 6 u
= 6 x 9
= 54
Answer(s): (a) 36; (b) 54