Five hours ago, a stallholder started his day with some oranges and persimmons in the ratio of 8 : 7. There were 385 persimmons. Some of the oranges were bought by Emma. As a result, the number of oranges became
45 of the persimmons.
- How many oranges did the stallholder have at first?
- How many persimmons did the stallholder have to sell in order to have an equal number of oranges and persimmons?
|
Oranges |
Persimmons |
Before |
8x5 = 40 u |
7x5 = 35 u |
Change |
- ? |
|
After |
4x7 = 28 u |
5x7 = 35 u |
(a)
The number of persimmons remains unchanged. Make the number of persimmons the same. LCM of 7 and 5 is 35.
35 u = 385
1 u = 385 ÷ 35 = 11
Number of oranges that the stallholder had at first
= 40 u
= 40 x 11
= 440
(b)
Number of persimmons that the stallholder had to sell to have an equal number of oranges and persimmons
= 35 u - 28 u
= 7 u
= 7 x 11
= 77
Answer(s): (a) 440; (b) 77