Eight hours ago, a stallholder started his day with some pears and kiwis in the ratio of 7 : 4. There were 60 kiwis. Some of the pears were bought by Erika. As a result, the number of pears became
25 of the kiwis.
- How many pears did the stallholder have left?
- How many pears did the stallholder have to buy in order to have an equal number of pears and kiwis?
|
Pears |
Kiwis |
Before |
7x5 = 35 u |
4x5 = 20 u |
Change |
- ? |
|
After |
2x4 = 8 u |
5x4 = 20 u |
(a)
The number of kiwis remains unchanged. Make the number of kiwis the same. LCM of 4 and 5 is 20.
20 u = 60
1 u = 60 ÷ 20 = 3
Number of pears that the stallholder had left
= 8 u
= 8 x 3
= 24
(b)
Number of pears that the stallholder had to buy to have an equal number of pears and kiwis
= 20 u - 8 u
= 12 u
= 12 x 3
= 36
Answer(s): (a) 24; (b) 36