Seth had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market M and the ratio of chikoos to oranges was 1 : 4. When he reached Market N, he unloaded
56 of the oranges and some chikoos from his van. The ratio of chikoos to oranges became 3 : 4. At Market P, 60 chikoos and 45 oranges were collected and the number of chikoos to oranges became the same.
- How many fruits were there on his van after visiting Market P?
- How many chikoos were delivered to Market N?
|
Location |
Chikoos |
Oranges |
Comparing chikoos and oranges at first |
Market M |
1x6 = 6 u |
4x6 = 24 u |
Before 1 |
Market M |
6 u |
6x4 = 24 u |
Change 1 |
Market N |
- ? |
- 5x4 = - 20 u |
After 1 |
Market P |
3 u |
1x4 = 4 u |
Before 2 |
Market P |
3x1 = 3 u |
4x1 = 4 u |
Change 2 |
Market P |
+ 60 |
+ 45 |
After 2 |
Market P |
3 u + 60 |
4 u + 45 |
(a)
The number of oranges after unloading at Market N is repeated. Make the number of oranges left after unloading at Market N the same. LCM of 4 and 1 is 4.
The number of oranges collected at Market M is repeated. Make the number of oranges collected at Market M the same by multiplying 4 by 6.
The number of chikoos and oranges in the end is the same.
4 u + 45 = 3 u + 60
4 u - 3 u = 60 - 45
1 u = 15
Number of chikoos on his van after collecting from Market P
= 3 u + 60
= 3 x 15 + 60
= 45 + 60
= 105
Number of fruits on his van after collecting from Market P
= 2 x 105
= 210
(b)
Number of chikoos delivered to Market N
= 6 u - 3 u
= 3 u
= 3 x 15
= 45
Answer(s): (a) 210; (b) 45