Perry had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart T and the ratio of passion fruits to pears was 1 : 2. When he reached Mart U, he unloaded
78 of the pears and some passion fruits from his lorry. The ratio of passion fruits to pears became 2 : 3. At Mart V, 39 passion fruits and 37 pears were collected and the number of passion fruits to pears became the same.
- How many fruits were there on his lorry after visiting Mart V?
- How many passion fruits were delivered to Mart U?
|
Location |
Passion Fruits |
Pears |
Comparing passion fruits and pears at first |
Mart T |
1x12 = 12 u |
2x12 = 24 u |
Before 1 |
Mart T |
12 u |
8x3 = 24 u |
Change 1 |
Mart U |
- ? |
- 7x3 = - 21 u |
After 1 |
Mart V |
2 u |
1x3 = 3 u |
Before 2 |
Mart V |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Mart V |
+ 39 |
+ 37 |
After 2 |
Mart V |
2 u + 39 |
3 u + 37 |
(a)
The number of pears after unloading at Mart U is repeated. Make the number of pears left after unloading at Mart U the same. LCM of 3 and 1 is 3.
The number of pears collected at Mart T is repeated. Make the number of pears collected at Mart T the same by multiplying 2 by 12.
The number of passion fruits and pears in the end is the same.
3 u + 37 = 2 u + 39
3 u - 2 u = 39 - 37
1 u = 2
Number of passion fruits on his lorry after collecting from Mart V
= 2 u + 39
= 2 x 2 + 39
= 4 + 39
= 43
Number of fruits on his lorry after collecting from Mart V
= 2 x 43
= 86
(b)
Number of passion fruits delivered to Mart U
= 12 u - 2 u
= 10 u
= 10 x 2
= 20
Answer(s): (a) 86; (b) 20