Elijah had to collect some fruits from two shops and deliver some fruits to another shop. He collected from Shop P and the ratio of pears to chikoos was 3 : 4. When he reached Shop Q, he unloaded
34 of the chikoos and some pears from his lorry. The ratio of pears to chikoos became 2 : 3. At Shop R, 51 pears and 48 chikoos were collected and the number of pears to chikoos became the same.
- How many fruits were there on his lorry after visiting Shop R?
- How many pears were delivered to Shop Q?
|
Location |
Pears |
Chikoos |
Comparing pears and chikoos at first |
Shop P |
3x3 = 9 u |
4x3 = 12 u |
Before 1 |
Shop P |
9 u |
4x3 = 12 u |
Change 1 |
Shop Q |
- ? |
- 3x3 = - 9 u |
After 1 |
Shop R |
2 u |
1x3 = 3 u |
Before 2 |
Shop R |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Shop R |
+ 51 |
+ 48 |
After 2 |
Shop R |
2 u + 51 |
3 u + 48 |
(a)
The number of chikoos after unloading at Shop Q is repeated. Make the number of chikoos left after unloading at Shop Q the same. LCM of 3 and 1 is 3.
The number of chikoos collected at Shop P is repeated. Make the number of chikoos collected at Shop P the same by multiplying 4 by 3.
The number of pears and chikoos in the end is the same.
3 u + 48 = 2 u + 51
3 u - 2 u = 51 - 48
1 u = 3
Number of pears on his lorry after collecting from Shop R
= 2 u + 51
= 2 x 3 + 51
= 6 + 51
= 57
Number of fruits on his lorry after collecting from Shop R
= 2 x 57
= 114
(b)
Number of pears delivered to Shop Q
= 9 u - 2 u
= 7 u
= 7 x 3
= 21
Answer(s): (a) 114; (b) 21