Owen had to collect some fruits from two shops and deliver some fruits to another shop. He collected from Shop H and the ratio of pears to kiwis was 5 : 9. When he reached Shop J, he unloaded
56 of the kiwis and some pears from his lorry. The ratio of pears to kiwis became 2 : 3. At Shop K, 64 pears and 46 kiwis were collected and the number of pears to kiwis became the same.
- How many fruits were there on his lorry after visiting Shop K?
- How many pears were delivered to Shop J?
|
Location |
Pears |
Kiwis |
Comparing pears and kiwis at first |
Shop H |
5x2 = 10 u |
9x2 = 18 u |
Before 1 |
Shop H |
10 u |
6x3 = 18 u |
Change 1 |
Shop J |
- ? |
- 5x3 = - 15 u |
After 1 |
Shop K |
2 u |
1x3 = 3 u |
Before 2 |
Shop K |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Shop K |
+ 64 |
+ 46 |
After 2 |
Shop K |
2 u + 64 |
3 u + 46 |
(a)
The number of kiwis after unloading at Shop J is repeated. Make the number of kiwis left after unloading at Shop J the same. LCM of 3 and 1 is 3.
The number of kiwis collected at Shop H is repeated. Make the number of kiwis collected at Shop H the same by multiplying 9 by 2.
The number of pears and kiwis in the end is the same.
3 u + 46 = 2 u + 64
3 u - 2 u = 64 - 46
1 u = 18
Number of pears on his lorry after collecting from Shop K
= 2 u + 64
= 2 x 18 + 64
= 36 + 64
= 100
Number of fruits on his lorry after collecting from Shop K
= 2 x 100
= 200
(b)
Number of pears delivered to Shop J
= 10 u - 2 u
= 8 u
= 8 x 18
= 144
Answer(s): (a) 200; (b) 144