Luke had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market H and the ratio of pears to oranges was 1 : 2. When he reached Market J, he unloaded
56 of the oranges and some pears from his van. The ratio of pears to oranges became 1 : 2. At Market K, 51 pears and 36 oranges were collected and the number of pears to oranges became the same.
- How many fruits were there on his van after visiting Market K?
- How many pears were delivered to Market J?
|
Location |
Pears |
Oranges |
Comparing pears and oranges at first |
Market H |
1x6 = 6 u |
2x6 = 12 u |
Before 1 |
Market H |
6 u |
6x2 = 12 u |
Change 1 |
Market J |
- ? |
- 5x2 = - 10 u |
After 1 |
Market K |
1 u |
1x2 = 2 u |
Before 2 |
Market K |
1x1 = 1 u |
2x1 = 2 u |
Change 2 |
Market K |
+ 51 |
+ 36 |
After 2 |
Market K |
1 u + 51 |
2 u + 36 |
(a)
The number of oranges after unloading at Market J is repeated. Make the number of oranges left after unloading at Market J the same. LCM of 2 and 1 is 2.
The number of oranges collected at Market H is repeated. Make the number of oranges collected at Market H the same by multiplying 2 by 6.
The number of pears and oranges in the end is the same.
2 u + 36 = 1 u + 51
2 u - 1 u = 51 - 36
1 u = 15
Number of pears on his van after collecting from Market K
= 1 u + 51
= 1 x 15 + 51
= 15 + 51
= 66
Number of fruits on his van after collecting from Market K
= 2 x 66
= 132
(b)
Number of pears delivered to Market J
= 6 u - 1 u
= 5 u
= 5 x 15
= 75
Answer(s): (a) 132; (b) 75