Jeremy had to collect some fruits from two shops and deliver some fruits to another shop. He collected from Shop S and the ratio of pomegranates to oranges was 3 : 4. When he reached Shop T, he unloaded
1112 of the oranges and some pomegranates from his lorry. The ratio of pomegranates to oranges became 2 : 3. At Shop U, 57 pomegranates and 47 oranges were collected and the number of pomegranates to oranges became the same.
- How many fruits were there on his lorry after visiting Shop U?
- How many pomegranates were delivered to Shop T?
|
Location |
Pomegranates |
Oranges |
Comparing pomegranates and oranges at first |
Shop S |
3x9 = 27 u |
4x9 = 36 u |
Before 1 |
Shop S |
27 u |
12x3 = 36 u |
Change 1 |
Shop T |
- ? |
- 11x3 = - 33 u |
After 1 |
Shop U |
2 u |
1x3 = 3 u |
Before 2 |
Shop U |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Shop U |
+ 57 |
+ 47 |
After 2 |
Shop U |
2 u + 57 |
3 u + 47 |
(a)
The number of oranges after unloading at Shop T is repeated. Make the number of oranges left after unloading at Shop T the same. LCM of 3 and 1 is 3.
The number of oranges collected at Shop S is repeated. Make the number of oranges collected at Shop S the same by multiplying 4 by 9.
The number of pomegranates and oranges in the end is the same.
3 u + 47 = 2 u + 57
3 u - 2 u = 57 - 47
1 u = 10
Number of pomegranates on his lorry after collecting from Shop U
= 2 u + 57
= 2 x 10 + 57
= 20 + 57
= 77
Number of fruits on his lorry after collecting from Shop U
= 2 x 77
= 154
(b)
Number of pomegranates delivered to Shop T
= 27 u - 2 u
= 25 u
= 25 x 10
= 250
Answer(s): (a) 154; (b) 250