Jeremy had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart E and the ratio of starfruits to chikoos was 1 : 2. When he reached Mart F, he unloaded
910 of the chikoos and some starfruits from his vehicle. The ratio of starfruits to chikoos became 1 : 2. At Mart G, 49 starfruits and 35 chikoos were collected and the number of starfruits to chikoos became the same.
- How many fruits were there on his vehicle after visiting Mart G?
- How many starfruits were delivered to Mart F?
|
Location |
Starfruits |
Chikoos |
Comparing starfruits and chikoos at first |
Mart E |
1x10 = 10 u |
2x10 = 20 u |
Before 1 |
Mart E |
10 u |
10x2 = 20 u |
Change 1 |
Mart F |
- ? |
- 9x2 = - 18 u |
After 1 |
Mart G |
1 u |
1x2 = 2 u |
Before 2 |
Mart G |
1x1 = 1 u |
2x1 = 2 u |
Change 2 |
Mart G |
+ 49 |
+ 35 |
After 2 |
Mart G |
1 u + 49 |
2 u + 35 |
(a)
The number of chikoos after unloading at Mart F is repeated. Make the number of chikoos left after unloading at Mart F the same. LCM of 2 and 1 is 2.
The number of chikoos collected at Mart E is repeated. Make the number of chikoos collected at Mart E the same by multiplying 2 by 10.
The number of starfruits and chikoos in the end is the same.
2 u + 35 = 1 u + 49
2 u - 1 u = 49 - 35
1 u = 14
Number of starfruits on his vehicle after collecting from Mart G
= 1 u + 49
= 1 x 14 + 49
= 14 + 49
= 63
Number of fruits on his vehicle after collecting from Mart G
= 2 x 63
= 126
(b)
Number of starfruits delivered to Mart F
= 10 u - 1 u
= 9 u
= 9 x 14
= 126
Answer(s): (a) 126; (b) 126