Fabian had to collect some fruits from two stalls and deliver some fruits to another stall. He collected from Stall L and the ratio of pears to oranges was 1 : 4. When he reached Stall M, he unloaded
1112 of the oranges and some pears from his lorry. The ratio of pears to oranges became 3 : 4. At Stall N, 46 pears and 36 oranges were collected and the number of pears to oranges became the same.
- How many fruits were there on his lorry after visiting Stall N?
- How many pears were delivered to Stall M?
|
Location |
Pears |
Oranges |
Comparing pears and oranges at first |
Stall L |
1x12 = 12 u |
4x12 = 48 u |
Before 1 |
Stall L |
12 u |
12x4 = 48 u |
Change 1 |
Stall M |
- ? |
- 11x4 = - 44 u |
After 1 |
Stall N |
3 u |
1x4 = 4 u |
Before 2 |
Stall N |
3x1 = 3 u |
4x1 = 4 u |
Change 2 |
Stall N |
+ 46 |
+ 36 |
After 2 |
Stall N |
3 u + 46 |
4 u + 36 |
(a)
The number of oranges after unloading at Stall M is repeated. Make the number of oranges left after unloading at Stall M the same. LCM of 4 and 1 is 4.
The number of oranges collected at Stall L is repeated. Make the number of oranges collected at Stall L the same by multiplying 4 by 12.
The number of pears and oranges in the end is the same.
4 u + 36 = 3 u + 46
4 u - 3 u = 46 - 36
1 u = 10
Number of pears on his lorry after collecting from Stall N
= 3 u + 46
= 3 x 10 + 46
= 30 + 46
= 76
Number of fruits on his lorry after collecting from Stall N
= 2 x 76
= 152
(b)
Number of pears delivered to Stall M
= 12 u - 3 u
= 9 u
= 9 x 10
= 90
Answer(s): (a) 152; (b) 90