Perry had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart C and the ratio of chikoos to starfruits was 2 : 3. When he reached Mart D, he unloaded
34 of the starfruits and some chikoos from his van. The ratio of chikoos to starfruits became 2 : 3. At Mart E, 41 chikoos and 22 starfruits were collected and the number of chikoos to starfruits became the same.
- How many fruits were there on his van after visiting Mart E?
- How many chikoos were delivered to Mart D?
|
Location |
Chikoos |
Starfruits |
Comparing chikoos and starfruits at first |
Mart C |
2x4 = 8 u |
3x4 = 12 u |
Before 1 |
Mart C |
8 u |
4x3 = 12 u |
Change 1 |
Mart D |
- ? |
- 3x3 = - 9 u |
After 1 |
Mart E |
2 u |
1x3 = 3 u |
Before 2 |
Mart E |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Mart E |
+ 41 |
+ 22 |
After 2 |
Mart E |
2 u + 41 |
3 u + 22 |
(a)
The number of starfruits after unloading at Mart D is repeated. Make the number of starfruits left after unloading at Mart D the same. LCM of 3 and 1 is 3.
The number of starfruits collected at Mart C is repeated. Make the number of starfruits collected at Mart C the same by multiplying 3 by 4.
The number of chikoos and starfruits in the end is the same.
3 u + 22 = 2 u + 41
3 u - 2 u = 41 - 22
1 u = 19
Number of chikoos on his van after collecting from Mart E
= 2 u + 41
= 2 x 19 + 41
= 38 + 41
= 79
Number of fruits on his van after collecting from Mart E
= 2 x 79
= 158
(b)
Number of chikoos delivered to Mart D
= 8 u - 2 u
= 6 u
= 6 x 19
= 114
Answer(s): (a) 158; (b) 114