Bobby had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market C and the ratio of chikoos to pears was 2 : 3. When he reached Market D, he unloaded
78 of the pears and some chikoos from his vehicle. The ratio of chikoos to pears became 2 : 3. At Market E, 29 chikoos and 12 pears were collected and the number of chikoos to pears became the same.
- How many fruits were there on his vehicle after visiting Market E?
- How many chikoos were delivered to Market D?
|
Location |
Chikoos |
Pears |
Comparing chikoos and pears at first |
Market C |
2x8 = 16 u |
3x8 = 24 u |
Before 1 |
Market C |
16 u |
8x3 = 24 u |
Change 1 |
Market D |
- ? |
- 7x3 = - 21 u |
After 1 |
Market E |
2 u |
1x3 = 3 u |
Before 2 |
Market E |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Market E |
+ 29 |
+ 12 |
After 2 |
Market E |
2 u + 29 |
3 u + 12 |
(a)
The number of pears after unloading at Market D is repeated. Make the number of pears left after unloading at Market D the same. LCM of 3 and 1 is 3.
The number of pears collected at Market C is repeated. Make the number of pears collected at Market C the same by multiplying 3 by 8.
The number of chikoos and pears in the end is the same.
3 u + 12 = 2 u + 29
3 u - 2 u = 29 - 12
1 u = 17
Number of chikoos on his vehicle after collecting from Market E
= 2 u + 29
= 2 x 17 + 29
= 34 + 29
= 63
Number of fruits on his vehicle after collecting from Market E
= 2 x 63
= 126
(b)
Number of chikoos delivered to Market D
= 16 u - 2 u
= 14 u
= 14 x 17
= 238
Answer(s): (a) 126; (b) 238