Ken had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart V and the ratio of oranges to passion fruits was 7 : 8. When he reached Mart W, he unloaded
78 of the passion fruits and some oranges from his van. The ratio of oranges to passion fruits became 1 : 2. At Mart X, 48 oranges and 28 passion fruits were collected and the number of oranges to passion fruits became the same.
- How many fruits were there on his van after visiting Mart X?
- How many oranges were delivered to Mart W?
|
Location |
Oranges |
Passion Fruits |
Comparing oranges and passion fruits at first |
Mart V |
7x2 = 14 u |
8x2 = 16 u |
Before 1 |
Mart V |
14 u |
8x2 = 16 u |
Change 1 |
Mart W |
- ? |
- 7x2 = - 14 u |
After 1 |
Mart X |
1 u |
1x2 = 2 u |
Before 2 |
Mart X |
1x1 = 1 u |
2x1 = 2 u |
Change 2 |
Mart X |
+ 48 |
+ 28 |
After 2 |
Mart X |
1 u + 48 |
2 u + 28 |
(a)
The number of passion fruits after unloading at Mart W is repeated. Make the number of passion fruits left after unloading at Mart W the same. LCM of 2 and 1 is 2.
The number of passion fruits collected at Mart V is repeated. Make the number of passion fruits collected at Mart V the same by multiplying 8 by 2.
The number of oranges and passion fruits in the end is the same.
2 u + 28 = 1 u + 48
2 u - 1 u = 48 - 28
1 u = 20
Number of oranges on his van after collecting from Mart X
= 1 u + 48
= 1 x 20 + 48
= 20 + 48
= 68
Number of fruits on his van after collecting from Mart X
= 2 x 68
= 136
(b)
Number of oranges delivered to Mart W
= 14 u - 1 u
= 13 u
= 13 x 20
= 260
Answer(s): (a) 136; (b) 260