Jenson had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market T and the ratio of starfruits to pears was 5 : 6. When he reached Market U, he unloaded
1112 of the pears and some starfruits from his van. The ratio of starfruits to pears became 3 : 4. At Market V, 20 starfruits and 14 pears were collected and the number of starfruits to pears became the same.
- How many fruits were there on his van after visiting Market V?
- How many starfruits were delivered to Market U?
|
Location |
Starfruits |
Pears |
Comparing starfruits and pears at first |
Market T |
5x8 = 40 u |
6x8 = 48 u |
Before 1 |
Market T |
40 u |
12x4 = 48 u |
Change 1 |
Market U |
- ? |
- 11x4 = - 44 u |
After 1 |
Market V |
3 u |
1x4 = 4 u |
Before 2 |
Market V |
3x1 = 3 u |
4x1 = 4 u |
Change 2 |
Market V |
+ 20 |
+ 14 |
After 2 |
Market V |
3 u + 20 |
4 u + 14 |
(a)
The number of pears after unloading at Market U is repeated. Make the number of pears left after unloading at Market U the same. LCM of 4 and 1 is 4.
The number of pears collected at Market T is repeated. Make the number of pears collected at Market T the same by multiplying 6 by 8.
The number of starfruits and pears in the end is the same.
4 u + 14 = 3 u + 20
4 u - 3 u = 20 - 14
1 u = 6
Number of starfruits on his van after collecting from Market V
= 3 u + 20
= 3 x 6 + 20
= 18 + 20
= 38
Number of fruits on his van after collecting from Market V
= 2 x 38
= 76
(b)
Number of starfruits delivered to Market U
= 40 u - 3 u
= 37 u
= 37 x 6
= 222
Answer(s): (a) 76; (b) 222