Howard had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market C and the ratio of starfruits to chikoos was 1 : 2. When he reached Market D, he unloaded
78 of the chikoos and some starfruits from his vehicle. The ratio of starfruits to chikoos became 3 : 4. At Market E, 49 starfruits and 45 chikoos were collected and the number of starfruits to chikoos became the same.
- How many fruits were there on his vehicle after visiting Market E?
- How many starfruits were delivered to Market D?
|
Location |
Starfruits |
Chikoos |
Comparing starfruits and chikoos at first |
Market C |
1x16 = 16 u |
2x16 = 32 u |
Before 1 |
Market C |
16 u |
8x4 = 32 u |
Change 1 |
Market D |
- ? |
- 7x4 = - 28 u |
After 1 |
Market E |
3 u |
1x4 = 4 u |
Before 2 |
Market E |
3x1 = 3 u |
4x1 = 4 u |
Change 2 |
Market E |
+ 49 |
+ 45 |
After 2 |
Market E |
3 u + 49 |
4 u + 45 |
(a)
The number of chikoos after unloading at Market D is repeated. Make the number of chikoos left after unloading at Market D the same. LCM of 4 and 1 is 4.
The number of chikoos collected at Market C is repeated. Make the number of chikoos collected at Market C the same by multiplying 2 by 16.
The number of starfruits and chikoos in the end is the same.
4 u + 45 = 3 u + 49
4 u - 3 u = 49 - 45
1 u = 4
Number of starfruits on his vehicle after collecting from Market E
= 3 u + 49
= 3 x 4 + 49
= 12 + 49
= 61
Number of fruits on his vehicle after collecting from Market E
= 2 x 61
= 122
(b)
Number of starfruits delivered to Market D
= 16 u - 3 u
= 13 u
= 13 x 4
= 52
Answer(s): (a) 122; (b) 52