Jenson had to collect some fruits from two supermarkets and deliver some fruits to another supermarket. He collected from Supermarket G and the ratio of pears to oranges was 1 : 5. When he reached Supermarket H, he unloaded
910 of the oranges and some pears from his lorry. The ratio of pears to oranges became 2 : 3. At Supermarket J, 59 pears and 46 oranges were collected and the number of pears to oranges became the same.
- How many fruits were there on his lorry after visiting Supermarket J?
- How many pears were delivered to Supermarket H?
|
Location |
Pears |
Oranges |
Comparing pears and oranges at first |
Supermarket G |
1x6 = 6 u |
5x6 = 30 u |
Before 1 |
Supermarket G |
6 u |
10x3 = 30 u |
Change 1 |
Supermarket H |
- ? |
- 9x3 = - 27 u |
After 1 |
Supermarket J |
2 u |
1x3 = 3 u |
Before 2 |
Supermarket J |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Supermarket J |
+ 59 |
+ 46 |
After 2 |
Supermarket J |
2 u + 59 |
3 u + 46 |
(a)
The number of oranges after unloading at Supermarket H is repeated. Make the number of oranges left after unloading at Supermarket H the same. LCM of 3 and 1 is 3.
The number of oranges collected at Supermarket G is repeated. Make the number of oranges collected at Supermarket G the same by multiplying 5 by 6.
The number of pears and oranges in the end is the same.
3 u + 46 = 2 u + 59
3 u - 2 u = 59 - 46
1 u = 13
Number of pears on his lorry after collecting from Supermarket J
= 2 u + 59
= 2 x 13 + 59
= 26 + 59
= 85
Number of fruits on his lorry after collecting from Supermarket J
= 2 x 85
= 170
(b)
Number of pears delivered to Supermarket H
= 6 u - 2 u
= 4 u
= 4 x 13
= 52
Answer(s): (a) 170; (b) 52