Howard had to collect some fruits from two markets and deliver some fruits to another market. He collected from Market B and the ratio of pears to chikoos was 1 : 2. When he reached Market C, he unloaded
1112 of the chikoos and some pears from his van. The ratio of pears to chikoos became 1 : 2. At Market D, 45 pears and 29 chikoos were collected and the number of pears to chikoos became the same.
- How many fruits were there on his van after visiting Market D?
- How many pears were delivered to Market C?
|
Location |
Pears |
Chikoos |
Comparing pears and chikoos at first |
Market B |
1x12 = 12 u |
2x12 = 24 u |
Before 1 |
Market B |
12 u |
12x2 = 24 u |
Change 1 |
Market C |
- ? |
- 11x2 = - 22 u |
After 1 |
Market D |
1 u |
1x2 = 2 u |
Before 2 |
Market D |
1x1 = 1 u |
2x1 = 2 u |
Change 2 |
Market D |
+ 45 |
+ 29 |
After 2 |
Market D |
1 u + 45 |
2 u + 29 |
(a)
The number of chikoos after unloading at Market C is repeated. Make the number of chikoos left after unloading at Market C the same. LCM of 2 and 1 is 2.
The number of chikoos collected at Market B is repeated. Make the number of chikoos collected at Market B the same by multiplying 2 by 12.
The number of pears and chikoos in the end is the same.
2 u + 29 = 1 u + 45
2 u - 1 u = 45 - 29
1 u = 16
Number of pears on his van after collecting from Market D
= 1 u + 45
= 1 x 16 + 45
= 16 + 45
= 61
Number of fruits on his van after collecting from Market D
= 2 x 61
= 122
(b)
Number of pears delivered to Market C
= 12 u - 1 u
= 11 u
= 11 x 16
= 176
Answer(s): (a) 122; (b) 176