Archie had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart G and the ratio of pears to persimmons was 2 : 3. When he reached Mart H, he unloaded
910 of the persimmons and some pears from his vehicle. The ratio of pears to persimmons became 2 : 3. At Mart J, 41 pears and 36 persimmons were collected and the number of pears to persimmons became the same.
- How many fruits were there on his vehicle after visiting Mart J?
- How many pears were delivered to Mart H?
|
Location |
Pears |
Persimmons |
Comparing pears and persimmons at first |
Mart G |
2x10 = 20 u |
3x10 = 30 u |
Before 1 |
Mart G |
20 u |
10x3 = 30 u |
Change 1 |
Mart H |
- ? |
- 9x3 = - 27 u |
After 1 |
Mart J |
2 u |
1x3 = 3 u |
Before 2 |
Mart J |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Mart J |
+ 41 |
+ 36 |
After 2 |
Mart J |
2 u + 41 |
3 u + 36 |
(a)
The number of persimmons after unloading at Mart H is repeated. Make the number of persimmons left after unloading at Mart H the same. LCM of 3 and 1 is 3.
The number of persimmons collected at Mart G is repeated. Make the number of persimmons collected at Mart G the same by multiplying 3 by 10.
The number of pears and persimmons in the end is the same.
3 u + 36 = 2 u + 41
3 u - 2 u = 41 - 36
1 u = 5
Number of pears on his vehicle after collecting from Mart J
= 2 u + 41
= 2 x 5 + 41
= 10 + 41
= 51
Number of fruits on his vehicle after collecting from Mart J
= 2 x 51
= 102
(b)
Number of pears delivered to Mart H
= 20 u - 2 u
= 18 u
= 18 x 5
= 90
Answer(s): (a) 102; (b) 90