Bryan had to collect some fruits from two stalls and deliver some fruits to another stall. He collected from Stall C and the ratio of chikoos to starfruits was 1 : 3. When he reached Stall D, he unloaded
78 of the starfruits and some chikoos from his vehicle. The ratio of chikoos to starfruits became 2 : 3. At Stall E, 21 chikoos and 10 starfruits were collected and the number of chikoos to starfruits became the same.
- How many fruits were there on his vehicle after visiting Stall E?
- How many chikoos were delivered to Stall D?
|
Location |
Chikoos |
Starfruits |
Comparing chikoos and starfruits at first |
Stall C |
1x8 = 8 u |
3x8 = 24 u |
Before 1 |
Stall C |
8 u |
8x3 = 24 u |
Change 1 |
Stall D |
- ? |
- 7x3 = - 21 u |
After 1 |
Stall E |
2 u |
1x3 = 3 u |
Before 2 |
Stall E |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Stall E |
+ 21 |
+ 10 |
After 2 |
Stall E |
2 u + 21 |
3 u + 10 |
(a)
The number of starfruits after unloading at Stall D is repeated. Make the number of starfruits left after unloading at Stall D the same. LCM of 3 and 1 is 3.
The number of starfruits collected at Stall C is repeated. Make the number of starfruits collected at Stall C the same by multiplying 3 by 8.
The number of chikoos and starfruits in the end is the same.
3 u + 10 = 2 u + 21
3 u - 2 u = 21 - 10
1 u = 11
Number of chikoos on his vehicle after collecting from Stall E
= 2 u + 21
= 2 x 11 + 21
= 22 + 21
= 43
Number of fruits on his vehicle after collecting from Stall E
= 2 x 43
= 86
(b)
Number of chikoos delivered to Stall D
= 8 u - 2 u
= 6 u
= 6 x 11
= 66
Answer(s): (a) 86; (b) 66