Paul had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart M and the ratio of starfruits to pears was 5 : 8. When he reached Mart N, he unloaded
1112 of the pears and some starfruits from his lorry. The ratio of starfruits to pears became 1 : 2. At Mart P, 23 starfruits and 20 pears were collected and the number of starfruits to pears became the same.
- How many fruits were there on his lorry after visiting Mart P?
- How many starfruits were delivered to Mart N?
|
Location |
Starfruits |
Pears |
Comparing starfruits and pears at first |
Mart M |
5x3 = 15 u |
8x3 = 24 u |
Before 1 |
Mart M |
15 u |
12x2 = 24 u |
Change 1 |
Mart N |
- ? |
- 11x2 = - 22 u |
After 1 |
Mart P |
1 u |
1x2 = 2 u |
Before 2 |
Mart P |
1x1 = 1 u |
2x1 = 2 u |
Change 2 |
Mart P |
+ 23 |
+ 20 |
After 2 |
Mart P |
1 u + 23 |
2 u + 20 |
(a)
The number of pears after unloading at Mart N is repeated. Make the number of pears left after unloading at Mart N the same. LCM of 2 and 1 is 2.
The number of pears collected at Mart M is repeated. Make the number of pears collected at Mart M the same by multiplying 8 by 3.
The number of starfruits and pears in the end is the same.
2 u + 20 = 1 u + 23
2 u - 1 u = 23 - 20
1 u = 3
Number of starfruits on his lorry after collecting from Mart P
= 1 u + 23
= 1 x 3 + 23
= 3 + 23
= 26
Number of fruits on his lorry after collecting from Mart P
= 2 x 26
= 52
(b)
Number of starfruits delivered to Mart N
= 15 u - 1 u
= 14 u
= 14 x 3
= 42
Answer(s): (a) 52; (b) 42