Jack had to collect some fruits from two stalls and deliver some fruits to another stall. He collected from Stall X and the ratio of mangoes to persimmons was 2 : 3. When he reached Stall Y, he unloaded
34 of the persimmons and some mangoes from his lorry. The ratio of mangoes to persimmons became 2 : 3. At Stall Z, 39 mangoes and 24 persimmons were collected and the number of mangoes to persimmons became the same.
- How many fruits were there on his lorry after visiting Stall Z?
- How many mangoes were delivered to Stall Y?
|
Location |
Mangoes |
Persimmons |
Comparing mangoes and persimmons at first |
Stall X |
2x4 = 8 u |
3x4 = 12 u |
Before 1 |
Stall X |
8 u |
4x3 = 12 u |
Change 1 |
Stall Y |
- ? |
- 3x3 = - 9 u |
After 1 |
Stall Z |
2 u |
1x3 = 3 u |
Before 2 |
Stall Z |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Stall Z |
+ 39 |
+ 24 |
After 2 |
Stall Z |
2 u + 39 |
3 u + 24 |
(a)
The number of persimmons after unloading at Stall Y is repeated. Make the number of persimmons left after unloading at Stall Y the same. LCM of 3 and 1 is 3.
The number of persimmons collected at Stall X is repeated. Make the number of persimmons collected at Stall X the same by multiplying 3 by 4.
The number of mangoes and persimmons in the end is the same.
3 u + 24 = 2 u + 39
3 u - 2 u = 39 - 24
1 u = 15
Number of mangoes on his lorry after collecting from Stall Z
= 2 u + 39
= 2 x 15 + 39
= 30 + 39
= 69
Number of fruits on his lorry after collecting from Stall Z
= 2 x 69
= 138
(b)
Number of mangoes delivered to Stall Y
= 8 u - 2 u
= 6 u
= 6 x 15
= 90
Answer(s): (a) 138; (b) 90