The ratio of kiwis to persimmons is 3 : 7. If 48 persimmons are added, the ratio of kiwis to persimmons will be 3 : 11. How many less kiwis than persimmons are there in the end?
| |
Kiwis |
Persimmons |
| Before |
3 u |
7 u |
| Change |
|
+ 48 |
| After |
3 u |
11 u |
The number of kiwis at first and in the end remains unchanged.
Number of persimmons added
= 11 u - 7 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Number of less kiwis than persimmons in the end
= 11 u - 3 u
= 8 u
= 8 x 12
= 96
Answer(s): 96
