Box L and Box M have a total of 70 jelly beans. After 4 jelly beans were transferred from Box L to Box M, there were 6 times as many jelly beans in Box L as Box M. How many jelly beans were there in each box at first?
- Box L
- Box M
|
Box L |
Box M |
Total |
Before |
6 u + 4 |
1 u - 4 |
70 |
Change |
- 4 |
+ 4 |
|
After |
6 u |
1 u |
70 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 6 u + 1 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of jelly beans in Box L at first
= 6 u + 4
= 6 x 10 + 4
= 60 + 4
= 64
(b)
Number of jelly beans in Box M at first
= 1 u - 4
= 10 - 4
= 6
Answer(s): (a) 64; (b) 6