Bag E and Bag F have a total of 72 chocolate bars. After 8 chocolate bars were transferred from Bag E to Bag F, there were 5 times as many chocolate bars in Bag E as Bag F. How many chocolate bars were there in each bag at first?
- Bag E
- Bag F
|
Bag E |
Bag F |
Total |
Before |
5 u + 8 |
1 u - 8 |
72 |
Change |
- 8 |
+ 8 |
|
After |
5 u |
1 u |
72 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 5 u + 1 u
= 6 u
6 u = 72
1 u = 72 ÷ 6 = 12
Number of chocolate bars in Bag E at first
= 5 u + 8
= 5 x 12 + 8
= 60 + 8
= 68
(b)
Number of chocolate bars in Bag F at first
= 1 u - 8
= 12 - 8
= 4
Answer(s): (a) 68; (b) 4