Bag E and Bag F have a total of 72 candy canes. After 7 candy canes were transferred from Bag E to Bag F, there were 3 times as many candy canes in Bag E as Bag F. How many candy canes were there in each bag in the end?
- Bag E
- Bag F
|
Bag E |
Bag F |
Total |
Before |
3 u + 7 |
1 u - 7 |
72 |
Change |
- 7 |
+ 7 |
|
After |
3 u |
1 u |
72 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 3 u + 1 u
= 4 u
4 u = 72
1 u = 72 ÷ 4 = 18
Number of candy canes in Bag E in the end
= 3 u
= 3 x 18
= 54
(b)
Number of candy canes in Bag F in the end
= 1 u
= 18
Answer(s): (a) 54; (b) 18