Box E and Box F have a total of 68 sweets. After 3 sweets were transferred from Box E to Box F, there were 3 times as many sweets in Box E as Box F. How many sweets were there in each box in the end?
- Box E
- Box F
|
Box E |
Box F |
Total |
Before |
3 u + 3 |
1 u - 3 |
68 |
Change |
- 3 |
+ 3 |
|
After |
3 u |
1 u |
68 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 3 u + 1 u
= 4 u
4 u = 68
1 u = 68 ÷ 4 = 17
Number of sweets in Box E in the end
= 3 u
= 3 x 17
= 51
(b)
Number of sweets in Box F in the end
= 1 u
= 17
Answer(s): (a) 51; (b) 17