Bag U and Bag V have a total of 114 candy canes. After 6 candy canes were transferred from Bag U to Bag V, there were 5 times as many candy canes in Bag U as Bag V. How many candy canes were there in each bag in the end?
- Bag U
- Bag V
|
Bag U |
Bag V |
Total |
Before |
5 u + 6 |
1 u - 6 |
114 |
Change |
- 6 |
+ 6 |
|
After |
5 u |
1 u |
114 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 5 u + 1 u
= 6 u
6 u = 114
1 u = 114 ÷ 6 = 19
Number of candy canes in Bag U in the end
= 5 u
= 5 x 19
= 95
(b)
Number of candy canes in Bag V in the end
= 1 u
= 19
Answer(s): (a) 95; (b) 19