Bag K and Bag L have a total of 76 candy canes. After 3 candy canes were transferred from Bag K to Bag L, there were 3 times as many candy canes in Bag K as Bag L. How many candy canes were there in each bag in the end?
- Bag K
- Bag L
|
Bag K |
Bag L |
Total |
Before |
3 u + 3 |
1 u - 3 |
76 |
Change |
- 3 |
+ 3 |
|
After |
3 u |
1 u |
76 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 3 u + 1 u
= 4 u
4 u = 76
1 u = 76 ÷ 4 = 19
Number of candy canes in Bag K in the end
= 3 u
= 3 x 19
= 57
(b)
Number of candy canes in Bag L in the end
= 1 u
= 19
Answer(s): (a) 57; (b) 19