Basket B and Basket C have a total of 44 jelly beans. After 8 jelly beans were transferred from Basket B to Basket C, there were 3 times as many jelly beans in Basket B as Basket C. How many jelly beans were there in each basket at first?
- Basket B
- Basket C
|
Basket B |
Basket C |
Total |
Before |
3 u + 8 |
1 u - 8 |
44 |
Change |
- 8 |
+ 8 |
|
After |
3 u |
1 u |
44 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 3 u + 1 u
= 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Number of jelly beans in Basket B at first
= 3 u + 8
= 3 x 11 + 8
= 33 + 8
= 41
(b)
Number of jelly beans in Basket C at first
= 1 u - 8
= 11 - 8
= 3
Answer(s): (a) 41; (b) 3