Bag A and Bag B have a total of 140 lollipops. After 17 lollipops were transferred from Bag A to Bag B, there were 6 times as many lollipops in Bag A as Bag B. How many lollipops were there in each bag at first?
- Bag A
- Bag B
| |
Bag A |
Bag B |
Total |
| Before |
6 u + 17 |
1 u - 17 |
140 |
| Change |
- 17 |
+ 17 |
|
| After |
6 u |
1 u |
140 |
(a)
The total number of lollipops at first and in the end remains the same.
Total number of lollipops in the end
= 6 u + 1 u
= 7 u
7 u = 140
1 u = 140 ÷ 7 = 20
Number of lollipops in Bag A at first
= 6 u + 17
= 6 x 20 + 17
= 120 + 17
= 137
(b)
Number of lollipops in Bag B at first
= 1 u - 17
= 20 - 17
= 3
Answer(s): (a) 137; (b) 3
