Box E and Box F have a total of 112 jelly beans. After 13 jelly beans were transferred from Box E to Box F, there were 6 times as many jelly beans in Box E as Box F. How many jelly beans were there in each box in the end?
- Box E
- Box F
|
Box E |
Box F |
Total |
Before |
6 u + 13 |
1 u - 13 |
112 |
Change |
- 13 |
+ 13 |
|
After |
6 u |
1 u |
112 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 6 u + 1 u
= 7 u
7 u = 112
1 u = 112 ÷ 7 = 16
Number of jelly beans in Box E in the end
= 6 u
= 6 x 16
= 96
(b)
Number of jelly beans in Box F in the end
= 1 u
= 16
Answer(s): (a) 96; (b) 16