Box S and Box T have a total of 133 candy canes. After 9 candy canes were transferred from Box S to Box T, there were 6 times as many candy canes in Box S as Box T. How many candy canes were there in each box in the end?
- Box S
- Box T
|
Box S |
Box T |
Total |
Before |
6 u + 9 |
1 u - 9 |
133 |
Change |
- 9 |
+ 9 |
|
After |
6 u |
1 u |
133 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 133
1 u = 133 ÷ 7 = 19
Number of candy canes in Box S in the end
= 6 u
= 6 x 19
= 114
(b)
Number of candy canes in Box T in the end
= 1 u
= 19
Answer(s): (a) 114; (b) 19