Basket N and Basket P have a total of 28 candy canes. After 4 candy canes were transferred from Basket N to Basket P, there were 3 times as many candy canes in Basket N as Basket P. How many candy canes were there in each basket at first?
- Basket N
- Basket P
|
Basket N |
Basket P |
Total |
Before |
3 u + 4 |
1 u - 4 |
28 |
Change |
- 4 |
+ 4 |
|
After |
3 u |
1 u |
28 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 3 u + 1 u
= 4 u
4 u = 28
1 u = 28 ÷ 4 = 7
Number of candy canes in Basket N at first
= 3 u + 4
= 3 x 7 + 4
= 21 + 4
= 25
(b)
Number of candy canes in Basket P at first
= 1 u - 4
= 7 - 4
= 3
Answer(s): (a) 25; (b) 3