Box U and Box V have a total of 80 chocolate bars. After 4 chocolate bars were transferred from Box U to Box V, there were 3 times as many chocolate bars in Box U as Box V. How many chocolate bars were there in each box at first?
- Box U
- Box V
|
Box U |
Box V |
Total |
Before |
3 u + 4 |
1 u - 4 |
80 |
Change |
- 4 |
+ 4 |
|
After |
3 u |
1 u |
80 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 3 u + 1 u
= 4 u
4 u = 80
1 u = 80 ÷ 4 = 20
Number of chocolate bars in Box U at first
= 3 u + 4
= 3 x 20 + 4
= 60 + 4
= 64
(b)
Number of chocolate bars in Box V at first
= 1 u - 4
= 20 - 4
= 16
Answer(s): (a) 64; (b) 16