Basket A and Basket B have a total of 77 jelly beans. After 5 jelly beans were transferred from Basket A to Basket B, there were 6 times as many jelly beans in Basket A as Basket B. How many jelly beans were there in each basket at first?
- Basket A
- Basket B
|
Basket A |
Basket B |
Total |
Before |
6 u + 5 |
1 u - 5 |
77 |
Change |
- 5 |
+ 5 |
|
After |
6 u |
1 u |
77 |
(a)
The total number of jelly beans at first and in the end remains the same.
Total number of jelly beans in the end
= 6 u + 1 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of jelly beans in Basket A at first
= 6 u + 5
= 6 x 11 + 5
= 66 + 5
= 71
(b)
Number of jelly beans in Basket B at first
= 1 u - 5
= 11 - 5
= 6
Answer(s): (a) 71; (b) 6