Box H and Box J have a total of 120 sweets. After 15 sweets were transferred from Box H to Box J, there were 5 times as many sweets in Box H as Box J. How many sweets were there in each box at first?
- Box H
- Box J
| |
Box H |
Box J |
Total |
| Before |
5 u + 15 |
1 u - 15 |
120 |
| Change |
- 15 |
+ 15 |
|
| After |
5 u |
1 u |
120 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 120
1 u = 120 ÷ 6 = 20
Number of sweets in Box H at first
= 5 u + 15
= 5 x 20 + 15
= 100 + 15
= 115
(b)
Number of sweets in Box J at first
= 1 u - 15
= 20 - 15
= 5
Answer(s): (a) 115; (b) 5
