Basket K and Basket L have a total of 102 sweets. After 3 sweets were transferred from Basket K to Basket L, there were 5 times as many sweets in Basket K as Basket L. How many sweets were there in each basket in the end?
- Basket K
- Basket L
|
Basket K |
Basket L |
Total |
Before |
5 u + 3 |
1 u - 3 |
102 |
Change |
- 3 |
+ 3 |
|
After |
5 u |
1 u |
102 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 5 u + 1 u
= 6 u
6 u = 102
1 u = 102 ÷ 6 = 17
Number of sweets in Basket K in the end
= 5 u
= 5 x 17
= 85
(b)
Number of sweets in Basket L in the end
= 1 u
= 17
Answer(s): (a) 85; (b) 17