Bag J and Bag K have a total of 95 sweets. After 9 sweets were transferred from Bag J to Bag K, there were 4 times as many sweets in Bag J as Bag K. How many sweets were there in each bag in the end?
- Bag J
- Bag K
|
Bag J |
Bag K |
Total |
Before |
4 u + 9 |
1 u - 9 |
95 |
Change |
- 9 |
+ 9 |
|
After |
4 u |
1 u |
95 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 4 u + 1 u
= 5 u
5 u = 95
1 u = 95 ÷ 5 = 19
Number of sweets in Bag J in the end
= 4 u
= 4 x 19
= 76
(b)
Number of sweets in Bag K in the end
= 1 u
= 19
Answer(s): (a) 76; (b) 19