Bag T and Bag U have a total of 56 sweets. After 10 sweets were transferred from Bag T to Bag U, there were 3 times as many sweets in Bag T as Bag U. How many sweets were there in each bag at first?
- Bag T
- Bag U
| |
Bag T |
Bag U |
Total |
| Before |
3 u + 10 |
1 u - 10 |
56 |
| Change |
- 10 |
+ 10 |
|
| After |
3 u |
1 u |
56 |
(a)
The total number of sweets at first and in the end remains the same.
Total number of sweets in the end
= 3 u + 1 u
= 4 u
4 u = 56
1 u = 56 ÷ 4 = 14
Number of sweets in Bag T at first
= 3 u + 10
= 3 x 14 + 10
= 42 + 10
= 52
(b)
Number of sweets in Bag U at first
= 1 u - 10
= 14 - 10
= 4
Answer(s): (a) 52; (b) 4
