Bag L and Bag M have a total of 63 chocolate bars. After 2 chocolate bars were transferred from Bag L to Bag M, there were 6 times as many chocolate bars in Bag L as Bag M. How many chocolate bars were there in each bag in the end?
- Bag L
- Bag M
|
Bag L |
Bag M |
Total |
Before |
6 u + 2 |
1 u - 2 |
63 |
Change |
- 2 |
+ 2 |
|
After |
6 u |
1 u |
63 |
(a)
The total number of chocolate bars at first and in the end remains the same.
Total number of chocolate bars in the end
= 6 u + 1 u
= 7 u
7 u = 63
1 u = 63 ÷ 7 = 9
Number of chocolate bars in Bag L in the end
= 6 u
= 6 x 9
= 54
(b)
Number of chocolate bars in Bag M in the end
= 1 u
= 9
Answer(s): (a) 54; (b) 9