Basket H and Basket J have a total of 98 candy canes. After 12 candy canes were transferred from Basket H to Basket J, there were 6 times as many candy canes in Basket H as Basket J. How many candy canes were there in each basket in the end?
- Basket H
- Basket J
|
Basket H |
Basket J |
Total |
Before |
6 u + 12 |
1 u - 12 |
98 |
Change |
- 12 |
+ 12 |
|
After |
6 u |
1 u |
98 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 98
1 u = 98 ÷ 7 = 14
Number of candy canes in Basket H in the end
= 6 u
= 6 x 14
= 84
(b)
Number of candy canes in Basket J in the end
= 1 u
= 14
Answer(s): (a) 84; (b) 14